Batman Equation - Numberphile
Skills:
Maths for ML80%
Key Takeaways
The Batman Curve equation is explained and visualized, showcasing how it was created using a combination of curves and straight lines, with the help of imaginary numbers to hide unwanted parts of the curves. The equation is a viral hit and was designed by a High School teacher to draw the Batman logo.
Full Transcript
so we're going to do uh something with that looks really complicated something you know if you talk about math you go oh no that looks horrific then we'll see how how it turns out [Music] okay yes we've done it that is probably the most horrific equation we've ever done on number file but what does it mean well let's try this out we're going to plot it right we're going to draw a graph in my computer here and now I'm going to draw the graph and it should be let me make that bigger for you it's the equation Batman deserves but not the one he needs right now there go that is the Batman curve it was famous when it went viral last year uh High School teacher uh designed this curve this equation so that it would draw the Batman logo and he made it quite cleverly out of different curves and straight lines can I show you how he did it so here we've got some some things that you may be familiar with straight lines we can are quite easy to draw what he did though is we don't want a circle for Batman we want an ellipse has a slightly different equation so it looks like that now he turned this into his Batman Wings obviously we don't want the whole thing that's not what what the curve looked like he actually just used these two ends he found a way to multiply his equation and the effect was it hides some of the curve what happens here in this bit that's missing this becomes a complex number imaginary number which means you can't draw it and that's what he did he just carried on doing that he just used curves and straight lines and let me show you what they look like to make his Batman now he used six curves let's have a look at them so he used the ellipse and look this is quite clever this is the bottom of the Batman symbol uh these straight lines and these ones are going to form his ears very pointy ones there and then there you go some more curves that finishes off the picture you put it all together and that's what you get that's the Batman so he hid parts of it using imaginary numbers yeah using square roots which would turn some numbers that he doesn't want to B it into imaginary numbers it was a very clever way it's the same curves but now you can see he hidden some parts of it you put those together and you put them together by multiplying so he put it together he multiplied these equations together what did you get the Batman curve it went viral last year uh but I wanted to do it because I'm very much looking forward to the dark KN coming out dark light Rises
Original Description
The Batman Curve was a viral hit. Here we show you some of its building blocks.
More links & stuff in full description below ↓↓↓
Here's the old reddit post: http://www.reddit.com/r/pics/comments/j2qjc/do_you_like_batman_do_you_like_math_my_math/
Featuring Dr James Grime.
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And if you fancy plotting it...
http://www.google.com/#hl=en&output=search&sclient=psy-ab&q=2+sqrt(-abs(abs(x)-1)*abs(3-abs(x))%2F((abs(x)-1)*(3-abs(x))))(1%2Babs(abs(x)-3)%2F(abs(x)-3))sqrt(1-(x%2F7)%5E2)%2B(5%2B0.97(abs(x-.5)%2Babs(x%2B.5))-3(abs(x-.75)%2Babs(x%2B.75)))(1%2Babs(1-abs(x))%2F(1-abs(x)))%2C-3sqrt(1-(x%2F7)%5E2)sqrt(abs(abs(x)-4)%2F(abs(x)-4))%2Cabs(x%2F2)-0.0913722(x%5E2)-3%2Bsqrt(1-(abs(abs(x)-2)-1)%5E2)%2C(2.71052%2B(1.5-.5abs(x))-1.35526sqrt(4-(abs(x)-1)%5E2))sqrt(abs(abs(x)-1)%2F(abs(x)-1))%2B0.9&pbx=1&oq=2+sqrt(-abs(abs(x)-1)*abs(3-abs(x))%2F((abs(x)-1)*(3-abs(x))))(1%2Babs(abs(x)-3)%2F(abs(x)-3))sqrt(1-(x%2F7)%5E2)%2B(5%2B0.97(abs(x-.5)%2Babs(x%2B.5))-3(abs(x-.75)%2Babs(x%2B.75)))(1%2Babs(1-abs(x))%2F(1-abs(x)))%2C-3sqrt(1-(x%2F7)%5E2)sqrt(abs(abs(x)-4)%2F(abs(x)-4))%2Cabs(x%2F2)-0.0913722(x%5E2)-3%2Bsqrt(1-(abs(abs(x)-2)-1)%5E2)%2C(2.71052%2B(1.5-.5abs(x))-1.35526sqrt(4-(abs(x)-1)%5E2))sqrt(abs(abs(x)-1)%2F(abs(x)-1))%2B0.9& amp;aq=f&aqi=&aql=&gs_sm=3&gs_upl=1000l1000l0l1996l1l0l0l0l0l0l0l0ll0l0&bav=on.2,or.r_gc.r_pw.r_qf.,cf.osb&fp=ab651cf178b9de65&biw=1400&bih=732
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