LeetCode 1046: Last Stone Weight — Step-by-Step Visual Trace
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Learn to solve the Last Stone Weight problem on LeetCode by implementing a step-by-step solution using a priority queue
Action Steps
- Create a priority queue to store the stone weights
- Implement a loop to repeatedly remove the two heaviest stones from the queue and smash them together
- Calculate the new weight after smashing the stones and add it back to the queue if it's not zero
- Repeat the loop until at most one stone remains
- Return the weight of the last stone or 0 if no stones remain
Who Needs to Know This
Software engineers and developers can benefit from this problem to improve their problem-solving skills and learn how to use priority queues to solve complex problems
Key Insight
💡 Use a priority queue to efficiently remove and add stones during the smashing process
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Solve the Last Stone Weight problem on LeetCode using a priority queue! 🚀
Key Takeaways
Learn to solve the Last Stone Weight problem on LeetCode by implementing a step-by-step solution using a priority queue
Full Article
Given an array of stone weights, repeatedly smash the two heaviest stones together until at most one stone remains, returning the weight of the last stone or 0 if no stones remain.
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