Crack a Classic DSA Interview Question: Reverse a Linked List in Python!

📰 Medium · Python

Learn to reverse a singly linked list in Python, a common coding interview question, to improve your understanding of pointers and linked data structures.

intermediate Published 28 Apr 2026
Action Steps
  1. Initialize pointers by setting prev to None and current to the head of the list.
  2. Traverse the list using a while loop, saving the next node and reversing the current node's pointer.
  3. Update the prev and current pointers to move forward in the list.
  4. Return the new head node of the reversed list.
  5. Implement the algorithm in Python using a LinkedList class and a reverse method.
Who Needs to Know This

Software engineers and developers can benefit from this tutorial to improve their problem-solving skills and data structure knowledge, which is essential for coding interviews and real-world applications.

Key Insight

💡 Reversing a singly linked list requires initializing pointers, traversing the list, and updating the pointers to reverse the links.

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🔀 Reverse a singly linked list in Python! 🔀 Improve your coding skills with this common interview question. #python #linkedlist #codinginterview

Key Takeaways

Learn to reverse a singly linked list in Python, a common coding interview question, to improve your understanding of pointers and linked data structures.

Full Article

Title: Crack a Classic DSA Interview Question: Reverse a Linked List in Python!

URL Source: https://ianisharya.medium.com/crack-a-classic-dsa-interview-question-reverse-a-linked-list-in-python-af54d7a9c933?source=rss------python-5

Published Time: 2026-04-28T20:56:29Z

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# Crack a Classic DSA Interview Question: Reverse a Linked List in Python! | by Anish Arya | Apr, 2026 | Medium

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# **Crack a Classic DSA Interview Question: Reverse a Linked List in Python!**

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If you’re preparing for coding interviews, this one comes up a lot: **reversing a singly linked list**. It’s a fundamental problem that tests your understanding of pointers and linked data structures.

## Algorithm: Reverse a Singly Linked List

Input: Head node of a singly linked list Output: New head node of

the reversed list

1. Initialize pointers:

a. prev = None -> will keep track of the previous node.

b. current = head -> start traversing from the head of the list.

2. Traverse the list:

a. While current is not None:

i. Save the next node: next_node = current.next

ii. Reverse the current node’s pointer: current.next = prev

iii. Move prev forward: prev = current

iv. Move curr
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